FIN (EXTENDED SURFACE)

In the study of heat transfer, a 'fin' is a surface that extends from an object to increase the rate of heat transfer to or from the environment by increasing convection. The amount of conduction, convection, or radiation of an object determines the amount of heat it transfers. Increasing the temperature difference between the object and the environment, increasing the convection heat transfer coefficient, or increasing the surface area of the object increases the heat transfer. Sometimes it is not economical or it is not feasible to change the first two options. Adding a fin to an object, however, increases the surface area and can sometimes be an economical solution to heat transfer problems.

Contents
Simplified Case
Four Uniform Cross-sectional Area Cases
Fin Performance
Fin Uses
Footnotes
References

Simplified Case


To create a simplified equation for the heat transfer of a fin, many assumptions need to be made.
Assume:
# Steady state
# Constant material properties (independent of temperature)
# No heat transfer
# No internal heat generation
# One-dimensional conduction
# Uniform cross-sectional area
# Uniform convection across the surface area
With these assumptions, the conservation of energy can be used to create an energy balance for a differential cross section of the fin.[1]
q_x=q_{x+dx}+dq_{conv}
Fourier’s law states that
q_x=-kA_c left ( rac{dT}{dx}
ight ),
where A_c is the cross-sectional area of the differential element.[2] Therefore the conduction rate at x+dx can be expressed as
q_{x+dx}=q_x+left ( rac{dq_x}{dx}
ight )dx
Hence, it can also be expressed as
q_{x+dx}=-kA_cleft ( rac{dT}{dx}
ight )-k rac{d}{dx} left ( A_c rac{dT}{dx}
ight )dx.
Since the equation for heat flux is
q''=hleft (T_s-T_infty
ight )
then dq_{conv} is equal to
h
★ dA_s left(T-T_infty
ight)
where A_s is the surface area of the differential element. By substitution it is found that
rac{d^2T}{dx^2} = left ( rac{1}{A_c} rac{dA_c}{dx}
ight ) rac{dT}{dx} - left ( rac{1}{A_c} rac{h}{k} rac{dA_s}{dx}
ight ) left ( T - T_infty
ight )
This is the general equation for convection from extended surfaces. Applying certain boundary conditions will allow this equation to simplify.

Four Uniform Cross-sectional Area Cases


For all four cases, the above equation will simplify because the area is constant and
rac {dA_s}{dx} = P
where P is the perimeter of the cross-sectional area. Thus, the general equation for convection from extended surfaces with constant cross-sectional area simplifies to
rac{d^2T}{dx^2}= rac{hP}{kA_c}left(T-T_infty
ight).
The solution to the simplified equation is
heta(x)=C_1e^{mx}+C_2e^{-mx}
where m^2= rac{hP}{kA_c}
and heta_x=T(x)-T_infty.
The constants C_1 and C_2 can be found by applying the proper boundary conditions. All four cases have the boundary condition T(x=0)=T_b for the temperature at the base. The boundary condition at x=L, however, is different for all of them, where L is the length of the fin.
For the first case, the second boundary condition is that there is free convection at the tip. Therefore,
hA_cleft(T(L)-T_infty
ight)=-kA_cleft.left( rac{dT}{dx}
ight)
ight ert_{x=L}
which simplifies to
h heta(L)=-kleft. rac{d heta}{dx}
ight ert_{x=L}
Knowing that
heta_b=T_{base}-T_infty,
the equations can be combined to produce
hleft(C_1e^{mL}+C_2e^{-mL}
ight)=kmleft(C_2e^{-mL}-C_1e^{mL}
ight)
C_1 and C_2 can be solved to produce the temperature distribution, which is in the table below. Then applying Fourier’s law at the base of the fin, the heat transfer rate can be found.
Similar mathematical methods can be used to find the temperature distributions and heat transfer rates for other cases. For the second case, the tip is assumed to be adiabatic or completely insulated. Therefore at x=L,
rac{d heta}{dx}=0
because heat flux is 0 at an adiabatic tip. For the third case, the temperature at the tip is held constant. Therefore the boundary condition is
heta(L)= heta_L. For the fourth and final case, the fin is assumed to be infinitely long. Therefore the boundary condition is
lim_{L
ightarrow infty} heta_L=0,.
The temperature distributions and heat transfer rates can then be found for each case.
{| border="1"
|+ Temperature Distribution and Heat Transfer Rate for Fins of Uniform Cross Sectional Area
! Case !! Tip Condition (x=L) !! Temperature Distribution !! Fin Heat Transfer Rate
|-
|A || Convection heat transfer || rac{ heta}{ heta_b}= rac{cosh{m(L-x)}+left( rac{h}{mk}
ight)sinh {m(L-x)}}{cosh{mL}+left( rac{h}{mk}
ight)sinh{mL}} || sqrt{hPkA_c} heta_b rac{sinh {mL} + (h/mk) cosh {mL}}{cosh {mL} + (h/mk) sinh {mL}}
|-
|B || Adiabatic || rac{ heta}{ heta_b}= rac{cosh {m(l-x)}}{cosh {mL}} || sqrt{hPkA_c} heta_b anh {mL}
|-
|C || Constant Temperature || rac{ heta}{ heta_b}= rac{ rac{ heta_L}{ heta_b}sinh {mx} + sinh {m(L-x)}}{sinh {mL}} || sqrt{hPkA_c} heta_b rac{cosh {mL} - frac{ heta_L}{ heta_b}}{sinh {mL}}
|-
|D || Infinite Fin Length || rac{ heta}{ heta_b}=e^{-mx} || sqrt{hPkA_c} heta_b
|}

Fin Performance


Fin performance can be described in three different ways. The first is fin effectiveness. It is the ratio of the fin heat transfer rate to the heat transfer rate of the object if it had no fin. The formula for this is
epsilon_f=frac{q_f}{hA_{c,b} heta_b},
where A_{c,b} is the fin cross-sectional area at the base. Fin performance can also be characterized by fin efficiency. This is the ratio of the fin heat transfer rate to the heat transfer rate of the fin if the entire fin were at the base temperature.
eta_f=q_fhA_f heta_b
A_f in this equation is equal to the surface area of the fin. Fin efficiency will always be less than one. This is because assuming the temperature throughout the fin is at the base temperature would increase the heat transfer rate. The third way fin performance can be described is with overall surface efficiency.
eta_o= rac{q_t}{hA_t heta_b},
where A_t is the total area and q_t is the sum of the heat transfer rates of all the fins. This is the efficiency for an array of fins.

Fin Uses


Fins are most commonly used in heat exchanging devices such as radiators in cars and heat exchangers in power plants.[3][4] They are also used in newer technology such as hydrogen fuel cells.[5] Nature has also taken advantage of the phenomena of fins. The ears of jackrabbits act as fins to release heat from the blood that flows through them.[6]

Footnotes



1. Conservation of Energy
2. Fourier's Law of Heat Conduction
3. Radiator Fin Machine or Machinery
4. The Design of Chart Heat Exchangers
5. VII.H.4 Development of a Thermal and Water Management System for PEM Fuel Cells
6. Jackrabbit ears: surface temperatures and vascular responses


References



Fundamentals of Heat and Mass Transfer, , Frank, Incropera, John Wiley & Sons, 2007, ISBN 0-471-45728-0

This article provided by Wikipedia. To edit the contents of this article, click here for original source.

psst.. try this: add to faves