CHARACTERISTIC SUBGROUP
In mathematics, a 'characteristic subgroup' of a group ''G'' is a subgroup ''H'' that is invariant under each automorphism of ''G''. That is, if φ : ''G'' → ''G'' is a group automorphism (a bijective homomorphism from the group ''G'' to itself), then for every ''x'' in ''H'' we have φ(''x'') ∈ ''H'':
:
It follows that
:
In symbols, one denotes the fact that ''H'' is a characteristic subgroup of ''G'' by
:
In particular, characteristic subgroups are invariant under inner automorphisms, so they are normal subgroups. However, the converse is not true; for example, consider the Klein group ''V''4. Every subgroup of this group is normal; but all 6 permutations of the 3 non-identity elements are automorphisms, so the 3 subgroups of order 2 are not characteristic.
On the other hand, if ''H'' is a normal subgroup of ''G'', and there are no other subgroups of the same order, then ''H'' must be characteristic; since automorphisms are order-preserving.
A related concept is that of a 'distinguished subgroup'. In this case the subgroup ''H'' is invariant under the applications of surjective endomorphisms. For a finite group this is the same, because surjectivity implies injectivity, but not for an infinite group: a surjective endomorphism is not necessarily an automorphism.
For an even stronger constraint, a 'fully characteristic subgroup' (also called a 'fully invariant subgroup') ''H'' of a group ''G'' is a group remaining invariant under every endomorphism of ''G''; in other words, if ''f'' : ''G'' → ''G'' is any homomorphism, then ''f''(''H'') is a subgroup of ''H''.
Every subgroup that is fully characteristic is certainly distinguished and therefore characteristic; but a characteristic or even distinguished subgroup need not be fully characteristic. The center of a group is easily seen to always be a distinguished subgroup, but it is not always fully characteristic.
Consider the group ''G'' = S3 × Z2 (the group of order 12 which is the direct product of the symmetric group of order 6 and a cyclic group of order 2). The center of ''G'' is its second factor Z2. Note that the first factor S3 contains subgroups isomorphic to Z2, for instance {identity,(12)}; let ''f'': Z2 → S3 be the morphism mapping Z2 onto the indicated subgroup. Then the composition of the projection of ''G'' onto its second factor Z2, followed by ''f'', followed by the inclusion of S3 into ''G'' as its first factor, provides an endomorphism of ''G'' under which the image of the center Z2 is not contained in the center, so here the center is not a fully characteristic subgroup of ''G''.
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The derived subgroup (or commutator subgroup) of a group is always a fully characteristic subgroup, as is the torsion subgroup of an abelian group.
The property of being characteristic or fully characteristic is transitive; if ''H'' is a (fully) characteristic subgroup of ''K'', and ''K'' is a (fully) characteristic subgroup of ''G'', then ''H'' is a (fully) characteristic subgroup of ''G''.
Moreover, while it is not true that every normal subgroup of a normal subgroup is normal, it is true that every characteristic subgroup of a normal subgroup is normal. Similarly, while it is not true that every distinguished subgroup of a distinguished subgroup is distinguished, it is true that every fully characteristic subgroup of a distinguished subgroup is distinguished.
The relationship amongst these subgroup properties can be expressed as:
:subgroup ← normal subgroup ← characteristic subgroup ← distinguished subgroup ← fully characteristic subgroup
Every subgroup of a cyclic group is characteristic.
★ characteristically simple group.
:
It follows that
:
In symbols, one denotes the fact that ''H'' is a characteristic subgroup of ''G'' by
:
In particular, characteristic subgroups are invariant under inner automorphisms, so they are normal subgroups. However, the converse is not true; for example, consider the Klein group ''V''4. Every subgroup of this group is normal; but all 6 permutations of the 3 non-identity elements are automorphisms, so the 3 subgroups of order 2 are not characteristic.
On the other hand, if ''H'' is a normal subgroup of ''G'', and there are no other subgroups of the same order, then ''H'' must be characteristic; since automorphisms are order-preserving.
A related concept is that of a 'distinguished subgroup'. In this case the subgroup ''H'' is invariant under the applications of surjective endomorphisms. For a finite group this is the same, because surjectivity implies injectivity, but not for an infinite group: a surjective endomorphism is not necessarily an automorphism.
For an even stronger constraint, a 'fully characteristic subgroup' (also called a 'fully invariant subgroup') ''H'' of a group ''G'' is a group remaining invariant under every endomorphism of ''G''; in other words, if ''f'' : ''G'' → ''G'' is any homomorphism, then ''f''(''H'') is a subgroup of ''H''.
Every subgroup that is fully characteristic is certainly distinguished and therefore characteristic; but a characteristic or even distinguished subgroup need not be fully characteristic. The center of a group is easily seen to always be a distinguished subgroup, but it is not always fully characteristic.
| Contents |
| Example |
| Example |
| See also |
Example
Consider the group ''G'' = S3 × Z2 (the group of order 12 which is the direct product of the symmetric group of order 6 and a cyclic group of order 2). The center of ''G'' is its second factor Z2. Note that the first factor S3 contains subgroups isomorphic to Z2, for instance {identity,(12)}; let ''f'': Z2 → S3 be the morphism mapping Z2 onto the indicated subgroup. Then the composition of the projection of ''G'' onto its second factor Z2, followed by ''f'', followed by the inclusion of S3 into ''G'' as its first factor, provides an endomorphism of ''G'' under which the image of the center Z2 is not contained in the center, so here the center is not a fully characteristic subgroup of ''G''.
----
The derived subgroup (or commutator subgroup) of a group is always a fully characteristic subgroup, as is the torsion subgroup of an abelian group.
The property of being characteristic or fully characteristic is transitive; if ''H'' is a (fully) characteristic subgroup of ''K'', and ''K'' is a (fully) characteristic subgroup of ''G'', then ''H'' is a (fully) characteristic subgroup of ''G''.
Moreover, while it is not true that every normal subgroup of a normal subgroup is normal, it is true that every characteristic subgroup of a normal subgroup is normal. Similarly, while it is not true that every distinguished subgroup of a distinguished subgroup is distinguished, it is true that every fully characteristic subgroup of a distinguished subgroup is distinguished.
The relationship amongst these subgroup properties can be expressed as:
:subgroup ← normal subgroup ← characteristic subgroup ← distinguished subgroup ← fully characteristic subgroup
Example
Every subgroup of a cyclic group is characteristic.
See also
★ characteristically simple group.
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